14x^2+55x+50=0

Solution for 14x^2+55x+50=0 equation:

14x^2+55x+50=0

a = 14; b = 55; c = +50;
Δ = b2-4ac
Δ = 552-4·14·50
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-15}{2*14}=\frac{-70}{28}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+15}{2*14}=\frac{-40}{28}
=-1+3/7
$